Mathematics (Time and Work)By NexisGrow / October 21, 2024 Choose Your Language Mathematics (Time and Work) Key DetailsTopic – Time and WorkTime- 10 MinsTotal Questions – 10For SSC, BANKING, RAILWAY, DEFENCE and all other Exams 1 / 9 If 6 persons working 8 hours a day earn ₹8400 per week, then 9 persons working 6 hours a day will earn per week- 8,400 9,800 9,450 10,680 Earnings Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Earnings CalculationStep 1: Calculate the total hours worked by 6 personsTotal hours worked by 6 persons in a week: Total hours = 6 × 8 × 7 = 336 hours Step 2: Calculate the earning per hour for the groupEarning per hour: Earning per hour = 8400 / 336 = 25 ₹ per hour Step 3: Calculate the total hours worked by 9 personsTotal hours for 9 persons: Total hours = 9 × 6 × 7 = 378 hours Step 4: Calculate the earning for 9 persons working 6 hours a dayTotal earning for 9 persons: Total earning = 378 × 25 = 9450 ₹ ConclusionThus, 9 persons working 6 hours a day will earn: ₹9450 per week 2 / 9 A, B and C can do a job working alone in 50, 75 and 20 days respectively. They all work together for 4 days, then C quits. How many days will A and B take to finish the rest of the job? 18 Days 20 Days 22 Days 24 Days Work Calculation: A, B, and C body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: A, B, and CStep 1: Work done by A, B, and C in 1 dayWork done by A in 1 day: 1/50Work done by B in 1 day: 1/75Work done by C in 1 day: 1/20Step 2: Work done by A, B, and C together in one dayTotal work done in 1 day: 1/12Step 3: Work done in 4 daysWork done in 4 days: 1/3Step 4: Remaining workRemaining work: 2/3Step 5: Work done by A and B togetherWork done by A and B in 1 day: 1/30Step 6: Time taken to complete the remaining workDays taken by A and B to complete the remaining work: 20 days 3 / 9 A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day? 12 Days 10 Days 15 Days 20 Days Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: A, B, and C Working TogetherStep 1: Work done by A, B, and C in 1 dayWork done by A in 1 day: 1/20</ 4 / 9 A and B can do a piece of work in 20 days and 12 days respectively. A started the work alone and then after 4 days B joined him till the completion of the work. How long did the work last? 10 Days 20 Days 15 Days 6 Days Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: A and B Working TogetherStep 1: Work done by A and B in 1 dayWork done by A in 1 day: 1/20Work done by B in 1 day: 1/12Step 2: Work done by A in the first 4 daysWork done by A in 4 days: 4 × 1/20 = 1/5Remaining work: 1 – 1/5 = 4/5Step 3: Work done by A and B together in 1 dayThe total work done by A and B together in 1 day is:1/20 + 1/12 = 3/60 + 5/60 = 8/60 = 2/15Step 4: Days required to finish the remaining workRemaining work is 4/5, and A and B together can complete 2/15 of the work in 1 day. So, the number of days to complete the remaining work is:4/5 ÷ 2/15 = 6 daysStep 5: Total time to complete the workA worked alone for 4 days, and A and B worked together for 6 days. Therefore, the total time taken is:4 days + 6 days = 10 days 5 / 9 A and B working separately can do a piece of work in 10 days and 15 days respectively. If they work on alternate days beginning with A, in how many days will the work be completed? 18 13 12 6 Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: A and B Working on Alternate DaysStep 1: Work done by A and B in 1 dayWork done by A in 1 day: 1/10Work done by B in 1 day: 1/15Step 2: Work done in 2 days (A on 1st day, B on 2nd day)The total work done in 2 days is:1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6Thus, in 2 days, A and B together complete 1/6 of the total work.Step 3: Complete cyclesIn 6 cycles of 2 days (12 days), they complete:6 × 1/6 = 1 (the whole work)Step 4: ConclusionThe work will be completed in 12 days. 6 / 9 Vijay and Sahil together complete a piece of work in 40 days, Sahil and Ranjit can complete the same work in 48 days and Ranjit and Vijay can complete the same work in 60 days. In how many days can all the three complete the same work while working together? 16 24 32 38 Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: Vijay, Sahil, and RanjitStep 1: Equations for individual combinations of workersLet the work done by Vijay in one day be V, the work done by Sahil in one day be S, and the work done by Ranjit in one day be R.Vijay and Sahil: V + S = 1/40Sahil and Ranjit: S + R = 1/48Ranjit and Vijay: R + V = 1/60Step 2: Add all three equationsAdding the three equations:2(V + S + R) = 1/40 + 1/48 + 1/60Step 3: Calculate the sum of the right-hand sideThe least common denominator (LCM) of 40, 48, and 60 is 240. Converting the fractions:1/40 = 6/2401/48 = 5/2401/60 = 4/240Adding them together:6/240 + 5/240 + 4/240 = 15/240 = 1/16Step 4: Solve for V + S + RNow we have:2(V + S + R) = 1/16Dividing both sides by 2:V + S + R = 1/32Step 5: ConclusionVijay, Sahil, and Ranjit working together can complete the work in 32 days. 7 / 9 Seventy-five men are employed to lay down a railway line in 3 months. Due to certain emergency conditions, the work was to be finished in 18 days. How many more men should be employed to complete the work in the desired time? 300 325 350 375 Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work Calculation: Railway Line LayingStep 1: Calculate the total workInitially, 75 men were employed to complete the job in 3 months (90 days). The total work is:Total Work = 75 × 90 = 6750 man-daysStep 2: Calculate the required number of men for 18 daysLet the total number of men required to complete the work in 18 days be x. Since the total work remains the same, we have:x × 18 = 6750Step 3: Solve for xSolving for x:x = 6750 ÷ 18 = 375Step 4: Calculate the number of additional men neededThe original number of men employed was 75, so the additional number of men required is:375 – 75 = 300Thus, 300 more men should be employed to complete the work in 18 days. 8 / 9 Some carpenters promised to do a job in 9 days but 5 of them were absent and remaining men did the job in 12 days. The original number of carpenters was- 24 20 16 18 Carpenters Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Carpenters Work CalculationLet the original number of carpenters be x.Step 1: Calculate the total amount of workThe total work is given by the original number of carpenters and the number of days:Total Work = x × 9 man-daysStep 2: Calculate the total work done with reduced carpentersWhen 5 carpenters were absent, the remaining x – 5 carpenters took 12 days to finish the work. The total work can also be expressed as:Total Work = (x – 5) × 12 man-daysStep 3: Equating the two expressions for total workSince both expressions represent the same total work, we can equate them:x × 9 = (x – 5) × 12Step 4: Solve for xExpanding both sides:9x = 12(x – 5)9x = 12x – 60Bringing all terms involving x to one side:9x – 12x = -60-3x = -60x = 60 ÷ 3 = 20The original number of carpenters was 20. 9 / 9 5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join them so as to complete the work in 4 days, they need to work per day for: 8 Hours 9 Hours 10 Hours 12 Hours Work Calculation body { font-family: Arial, sans-serif; line-height: 1.6; margin: 20px; } .container { max-width: 800px; margin: 0 auto; } .formula { font-weight: bold; color: #333; } .result { font-weight: bold; color: green; }Work CalculationWe can solve this problem using the concept of work, which is calculated as:Total Work = Number of people × Number of days × Hours per dayStep 1: Calculate the total work with the original 5 personsNumber of persons = 5Number of days = 8Hours per day = 7Total Work = 5 × 8 × 7 = 280 man-hoursStep 2: Calculate the daily work requirement with 7 persons to complete the work in 4 daysTotal number of people now = 5 + 2 = 7Days to complete the work = 4Let the required hours per day be x.7 × 4 × x = 280 man-hoursStep 3: Solve for x28x = 280x = 280 ÷ 28 = 10 hours per dayThus, they need to work 10 hours per day to complete the work in 4 days. 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