Reasoning Quiz (Set-III)By NexisGrow / November 10, 2024 Choose Your Language Reasoning (Set -III) Key DetailsSubject – ReasoningTime- 5 MinsFor SSC, BANKING, RAILWAY, DEFENCE and all other ExamsAll the Best ! 1 / 10 1. If -3%1 = 3, 3%6 = -18 and -7%4 = 28, then find the value of -2%9 = ? 47 -63 18 -30 Solution to Custom Operation ProblemGiven the operation “%” where:-3 % 1 = 33 % 6 = -18-7 % 4 = 28Pattern Observed: The operation “%” takes the product of the two numbers and then reverses the sign:If the product is positive, the result is made negative.If the product is negative, the result is made positive.Step 1: Apply this pattern to -2 % 9:Calculate the product: -2 × 9 = -18Reverse the sign: -18 becomes 18Final Answer: -2 % 9 = 18 2 / 10 2. A series is given with one term missing. Choose the correct alternative from the given ones that will complete the series.Rajasthan, Madhya Pradesh, Maharashtra, ? Uttar Pradesh Jammu Kashmir Tamil Nadu Assam Series Completion ProblemThe given series is:Rajasthan, Madhya Pradesh, Maharashtra, ?Step-by-Step Analysis:The series consists of names of states in India, and they are listed in a certain order:RajasthanMadhya PradeshMaharashtraEach of these states is located in a specific geographical region of India, with the order roughly following a west-to-east pattern on the map.Based on this pattern, the next state in the sequence should be from the eastern part of India. Among the given options, Assam is the state that fits this pattern.The correct answer is Assam. 3 / 10 3. Weight of Alok is twice the weight of Karan. Weight of Karan is one-fourth of the weight of Roma. Weight of Roma is twice of the weight of Tipu. Weight of Tipu is twice of the weight of Shivam. The weight of Roma is greater than the weight of how many persons among Alok, Karan, Shivam and Tipu? 3 4 0 2 Weight Comparison ProblemWe are given the following relationships about the weights of Alok, Karan, Roma, Tipu, and Shivam:Weight of Alok is twice the weight of Karan.Weight of Karan is one-fourth of the weight of Roma.Weight of Roma is twice the weight of Tipu.Weight of Tipu is twice the weight of Shivam.Step-by-Step Analysis:Let’s represent the weights of the persons in terms of a variable:Let Shivam’s weight be represented by W.Weight of Tipu = 2W (since Tipu is twice the weight of Shivam).Weight of Roma = 2 * 2W = 4W (since Roma is twice the weight of Tipu).Weight of Karan = 1/4 * 4W = W (since Karan is one-fourth the weight of Roma).Weight of Alok = 2 * W = 2W (since Alok is twice the weight of Karan).Now, we compare Roma’s weight with the others:Roma’s weight = 4WRoma’s weight is greater than Alok’s weight = 2W.Roma’s weight is greater than Karan’s weight = W.Roma’s weight is greater than Tipu’s weight = 2W.Roma’s weight is greater than Shivam’s weight = W.Therefore, Roma’s weight is greater than the weights of Alok, Karan, Tipu, and Shivam. So Roma’s weight is greater than the weight of 4 persons.The weight of Roma is greater than the weight of 4 persons among Alok, Karan, Shivam, and Tipu. 4 / 10 4. . In a certain code language, “INSTANT” is written as “IOUWESZ”. How is “FORGET” written in thatcode language?(a) FPOGXI(b) FOSIGX(c) FPSKHW(d) FPTJIY FPOGXI FOSIGX FPSKHW FPTJIY Code Language ProblemIn a certain code language, “INSTANT” is written as “IOUWESZ”. We need to find how “FORGET” is written in that code language.Step-by-Step Analysis:We need to observe the pattern from the given example: “INSTANT” is written as “IOUWESZ”. Let’s analyze the transformation for each letter.First letter: I -> ISecond letter: N -> O (shifted +1)Third letter: S -> U (shifted +2)Fourth letter: T -> W (shifted +3)Fifth letter: A -> E (shifted +4)Sixth letter: N -> S (shifted +5)Seventh letter: T -> Z (shifted +6)Based on this pattern of shifting each letter by an increasing amount (starting from +1 for the second letter), we apply the same shifts to the word “FORGET”.First letter: F -> F (no change)Second letter: O -> P (+1 shift)Third letter: R -> O (+2 shift)Fourth letter: G -> G (+3 shift)Fifth letter: E -> X (+4 shift)Sixth letter: T -> I (+5 shift)Therefore, “FORGET” is written as “FPOGXI” in the code language.The correct answer is FPOGXI. 5 / 10 5. In a certain code language, ‘-‘ represents ‘x’, ‘÷’ represents ‘+’, ‘+’ represents ‘÷’ and ‘x’ represents ‘-‘. Find out the answer to the following question. 2 x 12 ÷ 32 – 5 + 4 = ? 17 34 28 30 Solution to Coded Math ExpressionIn the given code language:‘-‘ represents ‘x‘ (multiplication)‘÷’ represents ‘+‘ (addition)‘+’ represents ‘÷‘ (division)‘x’ represents ‘–‘ (subtraction)We need to decode and solve: 2 x 12 ÷ 32 – 5 + 4Step 1: Replace symbols according to the code:Expression becomes: 2 – 12 + 32 x 5 ÷ 4Step 2: Apply standard order of operations (BODMAS):Division: 5 ÷ 4 = 1.25Multiplication: 32 x 1.25 = 40Subtraction: 2 – 12 = -10Addition: -10 + 40 = 30Final Answer: 30 6 / 10 6. In a certain code language, “TRUMP” is written as “46321” and “GRAIN” is written as “76598”. How is “GRUNT” written in that code language? 23684 23847 67834 76384 Solution to Code Language ProblemTo find the code for “GRUNT“, we match each letter to its corresponding number based on the given words:LetterCode from “TRUMP”Code from “GRAIN”T4–R66U3–M2–P1–G–7A–5I–9N–8Now, we can use these codes to write “GRUNT“:G → 7R → 6U → 3N → 8T → 4Therefore, “GRUNT” is written as: 76384. 7 / 10 7. If 16α1 = 8, 14α6 = 42 and 12α5 = 30, then find the value of 2α6 = ? 6 18 4 10 Solution to Mathematical OperationWe are given the following operations:16α1 = 814α6 = 4212α5 = 30Step 1: Let’s identify the pattern:The operation seems to involve multiplying the first number by the second and then performing some operation on the result.For example:16α1 = 16 × 1 = 16, but the result is 8. This suggests that we divide the product by 2.14α6 = 14 × 6 = 84, and dividing 84 by 2 gives 42, matching the result.12α5 = 12 × 5 = 60, and dividing 60 by 2 gives 30, which matches the result.Step 2: Now, apply the same operation to 2α6:2 × 6 = 12Dividing 12 by 2 gives: 12 ÷ 2 = 6Thus, the value of 2α6 = 6 8 / 10 8. Six persons A, B, C, D, E and F are standing in a circle. B is between F and C. A is between E and D. F isto the left of D. Who is between B and D?(a) E(b) C(c) F(d) A E C F A Circle Arrangement Problem body { font-family: Arial, sans-serif; margin: 20px; } h2 { color: #333399; } .steps { margin-top: 10px; } .result { font-weight: bold; color: #009900; margin-top: 10px; } .circle { display: flex; justify-content: center; align-items: center; width: 300px; height: 300px; border-radius: 50%; border: 2px solid black; position: relative; } .person { position: absolute; font-size: 16px; } .A { top: 10%; left: 50%; transform: translateX(-50%); } .B { left: 10%; top: 50%; transform: translateY(-50%); } .C { bottom: 10%; left: 50%; transform: translateX(-50%); } .D { right: 10%; top: 50%; transform: translateY(-50%); } .E { top: 50%; right: 10%; transform: translateY(-50%); } .F { bottom: 10%; right: 10%; }Circle Arrangement ProblemSix persons A, B, C, D, E, and F are standing in a circle. The given conditions are:B is between F and C.A is between E and D.F is to the left of D.Step-by-Step Analysis:Using the given clues, let’s arrange the people:Since B is between F and C, the order around the circle must be F, B, C.A is between E and D, which gives the order E, A, D.F is to the left of D, meaning F must be placed to the left of D.ABCDEFFrom the arrangement, the person who is between B and D is F. 9 / 10 9. An insect walks 15 cm East, then it turns to its right and walks for another 20 cm. then it turns rightand walks 4 cm, then it turns North and walks 20 cm, then finally it turns to its left and walks 2 cm.Where is the insect now with respect to its starting point?(a) 9 cm East(b) 21 cm East(c) 9 cm West(d) 21 cm West 9 cm East 21 cm East 9 cm West 21 cm West Insect Movement and Position CalculationAn insect starts at the origin and follows the following steps:It walks 15 cm East.Turns to its right and walks 20 cm.Turns right again and walks 4 cm.Turns North and walks 20 cm.Finally, it turns left and walks 2 cm.Step-by-Step Calculation:Starts at the origin (0,0) and walks 15 cm East: Position = (15, 0).Turns right (South) and walks 20 cm: Position = (15, -20).Turns right again (West) and walks 4 cm: Position = (11, -20).Turns North and walks 20 cm: Position = (11, 0).Finally, turns left (West) and walks 2 cm: Position = (9, 0).The insect is now 9 cm East of its starting position. 10 / 10 10. A woman while shopping in a mall pushes her trolley 20 metres through an alley which is going East, then she turns to her left and walks 30 metres, then she turns West and walks another 30 metres, then she turns South and walks 30 metres and then she turns West and walks 25 metres. Where is she now with reference to her starting position? 35 metres West 5 metres West 35 metres East 5 metres East Movement and Position CalculationA woman is shopping in a mall and takes the following steps:She pushes her trolley 20 metres East.She turns left and walks 30 metres North.She turns West and walks 30 metres.She turns South and walks 30 metres.Finally, she turns West and walks 25 metres.Step-by-Step Calculation:Starts at the origin (0,0) and walks 20 metres East: Position = (20, 0).Turns left (North) and walks 30 metres: Position = (20, 30).Turns West and walks 30 metres: Position = (10, 30).Turns South and walks 30 metres: Position = (10, 0).Finally, turns West and walks 25 metres: Position = (-15, 0).The woman is now 35 metres West of her starting position. Your score isThe average score is 70% 0% Restart quiz