HCF & LCM Chapter TestBy NexisGrow / September 11, 2024 Select Your Language oops! Time over LCM & HCF (Chapter Test – 1) All aspirants preparing for SSC, Banking, Railway, NDA, CDS, RPF, CISF, and other competitive exams can attempt this test to assess their preparation and performance. 1 / 10 The bells begin to toll together and they toll respectively at intervals of 6,7,8,9and 12 seconds. After how many seconds will they toll together again? 72 612 504 318 3) 504 secondLCM of6, 7,8,9 and 12seconds is 504 seconds 2 / 10 The product of two co-prime numbers is 117.Then their LCM is 117 9 13 39 Ans:1)117HCF of two Co-prime numbers are always 1HCF x LCM= First number x Second number=1171 x LCM = 117 3 / 10 The LCM of three different numbers is 120. Which of the following cannot be their HCF? 8 12 24 35 4)35120 =2x2x2x3x5Possible value of HCF are 4,8,12,24Hence 35 can not be HCF 4 / 10 A, B and C start running at the same time and at the same point in the same direction in a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds. After what time will they meet again at the starting point? 26 minutes 18 seconds 42 minutes 36 seconds 45 minutes 46 minutes 12 seconds 4) 46 minutes 12 secondsLCM= 2x2x7x9x11 = 2772 secondsThus, required time=2772 seconds = 46 minutes 12 seconds 5 / 10 The greatest 4-digit number exactly divisible by 10,15,201 is 9990 9960 9980 9995 2)9960LCM of 10,15,20 is 60Divide largest 4 digit number 9999 by 60 and remainder is 39Hence required number is 9999 -39 =9960 6 / 10 The LCM of two numbers is 2079 and their HCF is 27.If one of the numbers is 189, the other number is 297 584 189 216 1)297HCF x LCM= First number x Second number 2079 x 27 = 189 x Second numberSecond number=297 7 / 10 Find the least number which when divided separately by 15,20,36 and 48 leaves 3 as remainder in each case 183 243 483 723 4)723LCM of 15,20,36,48 is2x2x3x5x3x4 =720Required number is 720+3=723 8 / 10 The greatest number of four digits which when divided by 12,16 and 24 leave remainders 2, 6 and 14 respectively is 9974 9970 9807 9998 1)9974Since,12 – 2 =10,16 –6 =10 and 24 – 14 =10The LCM of 12,16 and 24 is 48.Therefore ,the largest 4-digit number exactly divisible by 48 is 9984. Hence, required number = 9984 – 10 = 9974 9 / 10 The product of two numbers is 4107.If the HCF of the numbers is 37,then a greater number is 185 111 107 101 2)111First number x Second number=HCF x LCM4107 = 37 x LCMLCM=111Numbers are 111 and 37 10 / 10 The LCM of two numbers is 4 times their HCF.The sum of LCM and HCF is 125.If one of the numbers is 100,then the other number is 5 25 100 125 Let LCM is L and HCF is HL = 4H and L +H =1255H = 125,H=25 L= 4H = 100L x H= 100 x Second numberSecond number = 25 Your score isThe average score is 27% 0% Restart quiz
