Reasoning Practice (Set-I)

let’s find the overlap of all these ranges:

From Arun’s estimate, the lower bound is 65 kg.
From his brother’s estimate, the upper bound is 70 kg.
From his mother’s view, the upper bound is further restricted to 68 kg.
So, the common range for Arun’s weight, based on all opinions, is between 65 kg and 68 kg.

The probable weights are: 65, 66, 67, and 68 kg.

Now, let’s calculate the average of these probable weights:

Average = 65+66+67+68/4 = 266/4 = 66.5kg

So, the average of the different probable weights of Arun is 66.5 kg.

Explanation: Statement B as you can find the support for this answer in the second sentence of the paragraph. This old generation of people tends to work independently, meaning they are self-employed and hardworking

Let’s analyze how the word “MADRAS” is coded as “NBESBT” and apply the same pattern to code “BOMBAY.”

1. **MADRAS → NBESBT**:
– M → N (M + 1)
– A → B (A + 1)
– D → E (D + 1)
– R → S (R + 1)
– A → B (A + 1)
– S → T (S + 1)

Each letter in “MADRAS” is shifted forward by 1 in the alphabet to get “NBESBT.”

2. Now, applying the same pattern to “BOMBAY”:
– B → C (B + 1)
– O → P (O + 1)
– M → N (M + 1)
– B → C (B + 1)
– A → B (A + 1)
– Y → Z (Y + 1)

Thus, “BOMBAY” is coded as **CPNCBZ**.

Clearly, the conclusion must be universally negative and should not contain the middle term. So, it follows that ‘No mango is cheap’. So if the mangoes are golden in color we may say golden-colored mangoes instead of just mangoes ‘. Thus, II follows.

The word “POSE” is coded as “OQNPRTDF” and apply the same pattern to code “TYPE.”

1. **POSE → OQNPRTDF**:
– The word **POSE** has 4 letters, and the code **OQNPRTDF** has 8 letters.
– The coding pattern seems to be:
– The first letter of the code is **1 letter before** the first letter of the word.
– The second letter of the code is **1 letter after** the first letter of the word.
– This alternating pattern is applied to each letter of the word.

Let’s break it down:
– P → O (P – 1)
– P → Q (P + 1)
– O → N (O – 1)
– O → P (O + 1)
– S → R (S – 1)
– S → T (S + 1)
– E → D (E – 1)
– E → F (E + 1)

So, each letter in “POSE” is encoded as two letters: one that is 1 letter before and one that is 1 letter after.

2. Now, applying the same pattern to the word **TYPE**:
– T → S (T – 1)
– T → U (T + 1)
– Y → X (Y – 1)
– Y → Z (Y + 1)
– P → O (P – 1)
– P → Q (P + 1)
– E → D (E – 1)
– E → F (E + 1)

Thus, “TYPE” is coded as **SUXZOQDF**.

Explanation: Consider the second letter of each option is static. Concentrating on the first and third letters is important. The entire series is in the reverse order of letters in alphabetical order. The first letter is in order F, G, H, I, J. The second and the fourth part are in the reverse order of the third and first letters. Hence, the missing part is the new letter

The family consists of:
Husband
Wife
Two sons
Two daughters
From the problem:

All the ladies (wife and two daughters) were invited to a dinner, so they are not at home.
Both sons went out to play, so they are also not at home.
The husband did not return from the office, so he is also not at home.
Thus, no one is at home

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

8 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday